Bulletproof SSL and TLS by Ivan Ristić

By Ivan Ristić

Knowing and deploying SSL/TLS and PKI to safe servers and internet purposes, by way of Ivan Ristić

For method directors, builders, and IT protection pros, this ebook presents a accomplished assurance of the ever-changing box of SSL/TLS and web PKI. Written through Ivan Ristić, a safety researcher and writer of SSL Labs, this booklet will educate you every little thing you must be aware of to guard your structures from eavesdropping and impersonation assaults.

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14 (even under the special case postulated in the theorem), and the claim follows. Having established the important direction, we now turn to the opposite one. That is, we assume that (G, E, D) is (uniformly) semantically secure and prove that it has (uniformly) indistinguishable encryptions. Again, the proof is by contradiction. 2 DEFINITIONS OF SECURITY input Z n . , letting h(plaintext) = Z n ). Indeed, this will be part of the construction presented next. , Y n ) consists of t(n) strings, each of length (n).

2. In addition, both algorithms get the length of X n . These algorithms then try to guess the value f (1n , X n ); namely, they try to infer information about the plaintext X n . Loosely speaking, in a semantically secure encryption scheme the ciphertext does not help in this inference task. , algorithm A ) that is not given the ciphertext at all. 1 refers to private-key encryption schemes. , G 1 (1n )) should be given to the adversary as an additional input. 2 The auxiliary input 1n is used for several purposes.

The reason is that for a public-key encryption scheme with a deterministic encryption algorithm E, given an encryption-key e and a pair of candidate plaintexts (x, y), one can easily distinguish E e (x) from E e (y) (by merely applying E e to x and comparing the result to the given ciphertext). In contrast, in case the encryption algorithm itself is randomized, the same plaintext can be encrypted in many exponentially different ways, under the same encryption-key. Furthermore, the probability that applying E e twice to the same message (while using independent randomization in E e ) results in the same ciphertext may be exponentially vanishing.

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